Earth travels around the sun in a nearly circular orbit at a mean distance of 1.5 x 10 ^11 m the sun’s mass is 1.99 x10^30 Kg. Calculate the Earth ‘s orbital period and orbital speed.

Respuesta :

The Earth ‘s orbital period and Orbital speed will be 2.6×10²⁸ second and 4.3 ×10¹⁵ m/sec, respectively.

What is earth orbital period?

The time required to complete an orbit around a planet is called as the orbital period.

The given data in the problem is;

r is the mean distance =  1.5 x 10 ^11 m

M is the sun’s mass = 1.99 x10^30 Kg

T is the Earth ‘s orbital period

V is the orbital speed.

The Earth ‘s orbital period  is found as;

[tex]\rm T = \frac{2 \times \pi r^\frac{3}{2} }{\sqrt{GM_{sun}} } \\\\\ \rm T = \frac{2 \times 3.14 (6.94 \times 10^{18})^\frac{3}{2} }{\sqrt{6.67 \times 10^{-11} 1.99 \times 10^{30}} } \\\\\ T =2.6 \times 10^{28} \ m/sec[/tex]

Hence, the Earth ‘s orbital period will be 2.6×10²⁸ second.

The orbital speed is found as;

[tex]\rm V = \sqrt{\frac{GM_{sun}}{r } }\\\\[/tex]

[tex]\rm V = \sqrt{\frac{GM_{sun}}{r } }\\\\\rm V = \sqrt{\frac{6.67 \times 10^{-11} \times 1.99 \times 10^{30}}{6.96 \times 10^8} }\\\\V=4.36 \times 10^{13}[/tex]

Hence, orbital speed will be 4.3 ×10¹⁵ m/sec.

To learn more about the orbital speed, refer to the link;

https://brainly.com/question/541239

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