Respuesta :
given:
trapezium
triangle
to find:
the area of the give shape.
solution:
Trapezium:
[tex]a = \frac{a + b}{2} h[/tex]
[tex]a = \frac{8 + 9}{2} \times 16[/tex]
[tex]a = 136 \: {cm}^{2} [/tex]
Triangle:
[tex]a = \frac{1}{2} bh[/tex]
[tex]a = \frac{1}{2} \times 5 \times 7[/tex]
[tex]a = 17.5 \: {cm}^{2} [/tex]
area of the shape:
[tex]136 + 17.5[/tex]
[tex]a = 153.5 \: {cm}^{2} [/tex]
to find the area of the mixed shape, we'll have to add the area of the trapezium and the triangle.
therefore,
[tex]area \: of \: trapezium = 136 \: {cm}^{2} [/tex]
[tex]area \: of \: triangle = 17.5 \: {cm}^{2} [/tex]
area of the mixed shape,
[tex]136 \: cm+ 17.5 \: cm[/tex]
[tex] = 153.5 \: {cm}^{2} [/tex]