a) The threshold frequency are electrons liberated from each of these surfaces will be 1.086 ×10¹⁵ Hz,0.887 ×10¹⁵ and 0.554×10¹⁵ Hz.
What is threshold frequency?
The threshold frequency of incoming radiation is the lowest frequency at which photoelectric emission or electron emission is impossible.
The threshold frequency is the light frequency that causes an electron to dislodge and emit from the metal's surface.
The given data in the problem is;
For mercury,[tex]\rm h_{V_M}=4.5 \times 1.6 \times 10^{-9}[/tex]
Threshold frequency is found as;
[tex]\rm v_m = \frac{4.5 \times 1.6 \times 10^{-19}}{6.625 \times 10^{-34}} \\\\ V_m=1.086 \times 10^{15}\ Hz[/tex]
For magnesium,
[tex]\rm V_{mg} =\frac{3.68 \times 1.6 \times 10^{-19}}{6.625 \times 10^{-34}} \\\\ V_{mg} =0.88887 \times 10^{15}\ Hz[/tex]
For lithium,
[tex]\rm V_L= \frac{2.3\times 1.6 \times 10^{-19}}{6.625 \times 10^{-34}} \\\\\ V_L=0.5554 \times 10^{15} \ Hz[/tex]
b) For mercury, Violet will not found in the visible region.
1. For mercury, Violet will not found in the visible region.
2. For magnesium Violet found in the visible region.
3. For Green, Green found in the visible region.
Hence, the threshold frequency are electrons liberated from each of these surfaces will be 1.086 ×10¹⁵ Hz,0.887 ×10¹⁵ and 0.554×10¹⁵ Hz.
To learn more about the threshold frequency, refer to the link;
https://brainly.com/question/2499414
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