What is the solution set of the following system of
equations?

Answer:
x=-5, x=0
Step-by-step explanation:
Substitute Y of first equation into second equation so:
3x+6 = [tex](x+4)^2-10[/tex]
Add 10 to both sides and expand brackets:
3x + 16 = [tex]x^2+8x+16[/tex]
Collect all terms onto one side:
[tex]x^2+5x=0[/tex]
Factorise:
[tex]x(x+5)=0[/tex]
The solutions therefore are:
x = -5
and
x = 0