Respuesta :

Answer:

D

Step-by-step explanation:

There are 7 letters in the word 'ALGEBRA'.

So the probability of picking any letter, in the beginning, is 1/7.

So the probability of picking any of the 'A's at the start is 2/7.

However for the second time, there'll only be 6 letters left and 1 A so the probability of getting the second A would be 1/6.

To find the combined probability, multiply these fractions together so:

[tex]\frac{2}{7}[/tex] times [tex]\frac{1}{6}[/tex]= [tex]\frac{2}{42} = \frac{1}{21}[/tex].

So the answer to the question would be D: 1 in 21.

profereyes12122

Answer:

D) 1 in 21

Step-by-step explanation:

The first draw:

[tex]\frac{2 (A's)}{7 (letters)} =2/7[/tex]

The second draw (no replace):

[tex]\frac{1(A's)}{6(letters)} =1/6[/tex]

The probability:
[tex]P=(\frac{2}{7})(\frac{1}{6} ) =\frac{(2)(1)}{(7)(6)} =\frac{2}{42}[/tex]

simplified:

[tex]P=\frac{1}{21}[/tex]

Hope this helps

Otras preguntas