The probability that it was Bus 65 will be 66.67%
Probability is defined as the chances of occurence of any random event. Now in the question we will find the probability of the bus 65 to pick up the passengers.
for that we will apply the formula for conditional probability.
[tex]P(X|B)=\dfrac{P(X\cap B)}{P(B)}[/tex]
Here X= Event that you take bus 65
S= event that you take bus 75
B=Bus picked up passengers
[tex]P(X|B)=\dfrac{P(X\cap B)}{P(B)}=\dfrac{P(X)\times P(B|X)}{P(X)(P(B|X)+P(S)(P(B|S)}[/tex]
[tex]P(X|B)= \dfrac{0.75\times 0.4}{(0.74\times 4)+(0.6\times 0.25)}}=\dfrac{0.5}{0.45}=0.667=66.67\%[/tex]
Hence the probability that it was Bus 65 will be 66.67%
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