Answer:
The answer for question 2 is:
x^2 - 25x - 26 =0
The answer for question 3 is:
[tex] - 3 {x}^{2} + 5x - 6 = 0[/tex]
Step-by-step explanation:
The general form of a quadratic equation is:
[tex]a {x}^{2} + bx + c = 0[/tex]
Therefore, for question 2 we have to ensure that the equation is in this format. The only thing to note is that the sign changes when a value goes to the other side of the equal sign. You can decide to carry over the x squared or you can carry over the 25x and the 26, it does not matter which you chose to do as the answer will still be correct. For question 3 we have to first clear the brackets before we can ensure it is in the general format.
[tex]x(x +5) = x \times x \: + x \times 5 \: which \:\: is \: equal \: to \: {x}^{2} + 5x[/tex]
Therefore the new equation would be:
[tex] {x}^{2} + 5x = 4 {x}^{2} + 6[/tex]
We do the same as we did in question 2.
