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A block, mass 8.00 kg, on a frictionless surface, is attached to a spring. The frequency is 4.00 Hz Amplitude is 3.00 meters. Find the frequency if the block is replaced with a 2.00 kg block while the amplitude is doubled.

Respuesta :

Answer:

ω = (K / M)^1/2       amplitude is not related to frequency

ω2 / ω1 = (M1 / M2)^1/2 = (8 / 2)^1/2 = 2

Since frequency is proportional to the angular speed

the frequency is doubled and is

f = 8 cps

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