The pressure of 1.27 L of a gas at 288°C, if the gas had a volume of 875 ml at 145 kPa and 176°C is 1.195 atm.
Ideal gas equation of any gas will be represented as:
PV = nRT, where
P = pressure
V = volume
n = moles
R = universal gas constant
T = temperature
First we calculate the moles of gas, when the volume of gas 875 ml at
145 kPa and 176°C as:
n = (1.431atm)(0.875L) / (0.082L.atm/K.mol)(449.15K)
n = 1.252 / 36.83 = 0.033 moles
Now we measure the pressure of 0.033 moles of gas of 1.27 L of a gas at 288°C as:
P = (0.033mol)(0.082L.atm/K.mol)(561K) / (1.27L) = 1.195 atm
Hence required pressure of gas is 1.195 atm.
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