If the value of the mean is 30.4. Then the standard deviation of the fuel efficiency rating will be 8.41.
It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.
The data displays fuel efficiency ratings for ten vehicles classified by the U.S. Environmental Protection Agency as hybrid vehicles.
(48, 40, 35, 34, 29, 27, 26, 24, 21, 20)
Then the standard deviation of the fuel efficiency rating will be
The mean value of the data set will be
[tex]\mu = \dfrac{48+40+35+34+29+27+26+24+21+20}{10}\\\\\mu = \dfrac{304}{10}\\\\\mu = 30.4[/tex]
Then the standard deviation is given as
[tex]\rm \sigma = \sqrt{\dfrac{\Sigma(x_i - \mu)^2}{n}}\\[/tex]
Then we have n = 10
[tex]\rm \sigma = \sqrt{\dfrac{(48-30.4)^2 + (40-30.4)^2 + (35-30.4)^2 + ....+(20-30.4)^2 }{10}}\\\\\sigma = 8.4047605557 \approx 8.41[/tex]
More about the standard deviation link is given below.
https://brainly.com/question/12402189
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