The scores on a certain standardized test follow a normal distribution. The mean score is 76, and the standard deviation is 8.
Find the percentage of test scores that are greater than 90. Round to the nearest percent and type your numerical answer below.

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About 4.01% of the test scores in the normal distribution that are greater than 90

What is an equation?

An equation is an expression that shows the relationship between two or more number and variables.

Z score is given by:

z = (raw score - mean) / standard deviation

Given that mean score is 76, and the standard deviation is 8.

For x > 90:

z = (90 - 76) / 8 = 1.75

P(z > 1.75) = 1 - P(z < 1.75) = 1 -  0.9599 = 0.0401

About 4.01% of the test scores in the normal distribution that are greater than 90

Find out more on equation at: https://brainly.com/question/2972832

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