Question 2(Multiple Choice Worth 2 points) (02.02 MC) Given the polynomial expression 6a2 + 6ca − 12a − 12c, factor completely. 6a(a – 2)(a + c) 6a(a – 2)(a – c) 6(a – 2)(a – c) 6(a – 2)(a + c)

Respuesta :

Answer:

6(a - 2)(a + c)

Step-by-step explanation:

Factor out common term 6:

= 6(a^2 + ac - 2a - 2c)

Factor a^2 + ac - 2a - 2c  (a + c) (a - 2)

= 6(a + c)(a - 2)

If you look at answer choice D, you will notice the two quantities switched around.  I'm pretty sure it doesn't matter.  So sorry if I'm wrong.

By using factorization, [tex]6a^{2} +6ca-12a-12c[/tex] = [tex]6(a+c)(a-2)[/tex].

What is factorization?

Factorization is defined as breaking an entity into a product of another entity, or factors, which when multiplied together give the original number.

Given polynomial expression

[tex]6a^{2} +6ca-12a-12c[/tex]

⇒ [tex]6(a^{2} +ca-2a-2c)[/tex]

⇒ [tex]6.a(a+c)-2(a+c)[/tex]

⇒ [tex]6(a+c)(a-2)[/tex]

By using factorization, [tex]6a^{2} +6ca-12a-12c[/tex] = [tex]6(a+c)(a-2)[/tex].

Find out more information about factorization here

https://brainly.com/question/1863222

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