Answer:
Discriminant is 0, 1 real solution
Step-by-step explanation:
Set the equation in form of [tex]\displaystyle \large{ax^2+bx+c=0}[/tex]:
[tex]\displaystyle \large{x^2+4x+1+3=0}\\\\\displaystyle \large{x^2+4x+4=0}[/tex]
Apply discriminant formula which is [tex]\displaystyle \large{b^2-4ac}[/tex]:
[tex]\displaystyle \large{D=4^2-4(1)(4)}\\\\\displaystyle \large{D=16-16}\\\\\displaystyle \large{D=0}[/tex]
Therefore, the discriminant is 0. Since D = 0, it’s defined that there are only 1 real solution.
