The area of the smaller parallelogram will be 8 square units.
The parallelogram is a quadrilateral whose two opposite sides are parallel to each other.
In the question the two corresponding sides of the two similar parallelogram are 4 and 12 so the ratio of the larger and the smaller parallelogram will be 3:1
Now the area of the smaller parallelogram will be calculated as
[tex](\dfrac{3}{1})^2=\dfrac{72}{A_s}[/tex]
[tex]A_s=\dfrac{72}{9}=8[/tex]
Hence the area of the smaller parallelogram will be 8 square units.
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