The probability that the archer will hit the bullseye exactly two out of five times is 0.3087
How to determine the probability?
The given parameters are:
Sample space, n = 5
Number of hits, x = 2
Probability of hit, p = 30%
The required probability is then calculated using the following binomial formula
[tex]P(x) = ^nC_x * p^x *(1 - p)^{n-x}[/tex]
So, we have:
[tex]P(2) = ^5C_2 * (30\%)^2 *(1 - 30\%)^{5-2}[/tex]
Evaluate the product
P(2) = 0.3087
Hence, the probability that the archer will hit the bullseye exactly two out of five times is 0.3087
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