Answer:
[tex]\Longrightarrow: \boxed{\sf{m=2n+1}}[/tex]
Step-by-step explanation:
To solve this problem, you have to isolate the term of m on one side of the equation.
4(m+3)-8n=16
First, add by 8n from both sides.
[tex]\Longrightarrow: \sf{4\left(m+3\right)-8n+8n=16+8n}[/tex]
Solve.
[tex]\Longrightarrow: \sf{4\left(m+3\right)=16+8n}[/tex]
Then, you divide by 4 from both sides.
[tex]\Longrightarrow: \sf{\dfrac{4\left(m+3\right)}{4}=\dfrac{16}{4}+\dfrac{8n}{4}}[/tex]
Solve.
16/4+8n/4=2(n+2)
m+3=2(n+2)
Subtract by 3 from both sides.
[tex]\Longrightarrow: \sf{m+3-3=2\left(n+2\right)-3}[/tex]
Solve.
[tex]\Longrightarrow: \boxed{\sf{m=2n+1}}[/tex]
- Therefore, the correct answer is m=2n+1.
I hope this helps, let me know if you have any questions.
