Volume of the solid obtained by
rotating the region bounded by [tex]y=\sqrt{}x,y=3[/tex] and the y-axis about the y-axis.
[tex]=f^3_0\pi x^2dy[/tex]
[tex]=\pi f^3_0x^2dy[/tex]
[tex]=\pi f^3_0[/tex] [tex]y^4dy[/tex] since [tex]y=\sqrt{}x[/tex]
[tex]=\pi [\frac{y^5}{5}]\frac{3}{0}[/tex]
[tex]=\pi (\frac{3^5}{5})[/tex]
[tex]=\frac{243\pi }{5}[/tex]
[tex]=48.6[/tex][tex]\pi[/tex]
So the required volume will be [tex]\frac{243\pi }{5}[/tex] cubic unit [tex]=4.86[/tex][tex]\pi[/tex] cubic unit
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