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A soccer player kicks a ball on the ground at an angle of 41 degrees and an initial velocity of 130 ft./sec. if the ball is not touched while in the air, when will it hit the ground? remember that the acceleration due to gravity is 32 ft./s^2
3.07 seconds
2.67 seconds
6.13 seconds
5.33 seconds

Respuesta :

oladayoademosu

If the ball has an initial velocity of 130 ft/s and an angle of 41°, the time it will take the ball to hit the ground is 5.33 seconds

Since the ball is a projectile, we need to find its time of flight for it to reach the ground

Time of flight of ball

The time of flight of the ball is the time it will take to hit the ground. It is given by

T = 2UsinФ/g where

  • U = speed of ball = 130 ft/s
  • Ф = angle of projection = 41° and
  • g = acceleration due to garvity = 32 ft/s²

Substituting the values of the variables into the equation, we have

T = 2UsinФ/g

T = 2 × 130 ft/s × sin41° ÷ 32 ft/s²

T = 260 ft/s × 0.6561 ÷ 32 ft/s²

T = 170.58 ft/s ÷ 32 ft/s²

T = 5.33 seconds

So, the time it will take the ball to hit the ground is 5.33 seconds

Learn more about time of flight here:

https://brainly.com/question/24136952

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