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It took 412.5 J of heat to raise the temperature of 24.6 g of a substance from 14.5°C to 52.6°C. What is the specific heat of the substance?

Respuesta :

If it took 412.5 J of heat to raise the temperature of 24.6 g of a substance from 14.5°C to 52.6°C, the specific heat of the substance is 0.44 J/g°C.

How to calculate specific heat of a substance?

The specific heat of a substance can be calculated by using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat absorbed or released
  • m = mass of substance
  • c = specific heat capacity
  • ∆T = change in temperature

412.5 = 24.6 × c × (52.6 - 14.5)

412.5 = 937.26c

c = 412.5/937.26

c = 0.44 J/g°C

Therefore, If it took 412.5 J of heat to raise the temperature of 24.6 g of a substance from 14.5°C to 52.6°C, the specific heat of the substance is 0.44 J/g°C.

Learn more about specific heat at: https://brainly.com/question/1747943

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