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9. you and your devious friends push a 1200 kg car along a level road, accelerating it from rest. the pushers transfer 6500 j of energy into the system and loses -2000. j in the
eth account due to friction.
how fast will the vehicle be traveling after the push?

Respuesta :

asuwafohjames

The speed of the vehicle after the push is 2.7 m/s.

What is velocity?

velocity is the rate of change of displacement.

To calculate the velocity of the vehicle, we use the formula below.

Formula:

  • v = √[2(W-W')/m]............... Equation 1

Where:

  • v = velocity of the car
  • W = work done by the pusher
  • W' = Work done by friction
  • m = mass of the car

From the question,

Given:

  • W = 6500 J
  • W' = 2000 J
  • m = 1200 kg

Substitute these values into equation 1

  • v = √[2(6500-2000)/1200]
  • v = √(7.5)
  • v = 2.7 m/s

Hence, the speed of the vehicle after the push is 2.7 m/s.

Learn more about velocity here:

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