Heat absorbed by ethyl alcohol is 925.82838 J.
The quantity of heat required to raise the temperature of one gram of a substance by one celsius degree.
Given data:
Mass of ethyl alcohol = 7.89g
Initial temperature = 25 °C
Final temperature = 72.7 °C
Heat absorbed by ethyl alcohol = ?
Solution:
Specific heat capacity of ethyl alcohol = 2.46 j/g.°C
Change in temperature = 72.7°C - 25 °C = 47.7 °C
Formula
Q = m. c. ΔT
Q = 7.89g × 2.46 j/g.°C × 47.7 °C
Q = 925.82838 J
Hence, heat absorbed by ethyl alcohol is 925.82838 J.
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