Raul's soccer team enters a tournament. He estimates that
his team has a 50% chance of winning each of the three
games they play. If they win all three games, they move to
the championship. To model his team's chance of going to
the championship, Raul performs a simulation using a
coin.

Respuesta :

Using the binomial distribution, it is found that there is a 0.125 = 12.5% probability that the team goes to the championship.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • His team has a p = 0.5 probability of winning each game.
  • The team plays 3 games, hence n = 3.

The team moves to the championship if they win all three games, hence the probability is P(X = 3), given as follows:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{3,3}.(0.5)^{3}.(0.5)^{0} = 0.125[/tex]

0.125 = 12.5% probability that the team goes to the championship.

More can be learned about the binomial distribution at https://brainly.com/question/24863377

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