Initially, there are 5 red beans and 9 black beans in a bag. then, 3 red beans and
3 black beans are added to the bag. if one bean is randomly chosen from the bag,
what is the probability that this bean is red?
first correct answer will get marked brainiest

I honestly don know but uh imma straight-up guess if there was 5 red beans and 9 black beans and I added 3 more red beans 3+5=8 so now 8 red beans then at 3 more black beans 9+3=12 so we would have more black beans then red beans so it would be most likely to grab a black bean.

Step-by-step explanation:

5 +3= 8 red beans

9 +3= 12 black beans

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Initially, there are 5 red beans and 9 black beans in a bag. then, 3 red beans and 3 black beans are added to the bag. if one bean is randomly chosen from the bag, what is the probability that this bean is red? first correct answer will get marked brainiest

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Initially, there are 5 red beans and 9 black beans in a bag. then, 3 red beans and
3 black beans are added to the bag. if one bean is randomly chosen from the bag,
what is the probability that this bean is red?
first correct answer will get marked brainiest