Answer:
C
Step-by-step explanation:
[tex]x = (- b + - \sqrt{ {b}^{2} - 4ac } ) \div 2[/tex]
[tex]x1 = (- ( - 1) - \sqrt{ {( - 1)}^{2} - 4 \times (1) \times ( - 3) }) \div 2 = \\( 1 - \sqrt{1 + 12}) \div 2 = (1 - \sqrt{13} )\div 2 [/tex]
[tex]x1 = ( - ( - 1) + \sqrt{ {( - 1)}^{2} - 4 \times (1) \times ( - 3) }) \div 2 = \\( 1 + \sqrt{1 + 12} ) \div 2=( 1 + \sqrt{13} ) \div 2[/tex]
