A 0.10kg ball at rest is hit by a golf club. The club applies a force of 700N to the ball but is only in contact with the ball for about .05s. How fast would the ball be moving after the impact?

Respuesta :

A ball at rest hit by a golf club has initial velocity zero. The ball will be moving after the impact at speed of  1.4 x 10⁵ m/s.

What is force?

The action of push or pull which changes the state of motion or rest of a body is called force.

The club applies a force of 700N to the ball and the time of impact is 0.05s. The mass of ball is 0.10kg.

The impact force F is equal to the change in momentum of the ball multiplied by time of impact t. The momentum is the product of mass m and velocity v after impact.

F= (mv -mu) x t

The ball is initially at rest, so u =0

F = mvt

Substitute the values into the above equation of force to find the velocity.

v = F / mt

v =700 / (0.10 x 0.05)

v = 1.4 x 10⁵ m/s

Thus, the ball will be moving after the impact at speed of  1.4 x 10⁵ m/s.

Learn more about force.

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