Answer:
[tex]\textsf{If }\: X \sim\textsf{N}(\mu,\sigma^2)\:\textsf{ then }\: \dfrac{X-\mu}{\sigma}=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)[/tex]
Therefore,
[tex]\textsf{If }\: X \sim \textsf{N}(33,4^2)\:\textsf{ then }\: \dfrac{X-33}{4}=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)[/tex]
[tex]X=29 \implies Z=\dfrac{29-33}{4} \implies Z= -1[/tex]
[tex]X=41 \implies Z=\dfrac{41-33}{4} \implies Z=2[/tex]
[tex]X=25 \implies Z=\dfrac{25-33}{4} \implies Z=-2[/tex]
No given lifespan is unusual, as they are all within 3 standard deviations of the mean.
