For a population of watermelons, 75.4 % of the watermelons have radii between 15.0 cm and 22.0 cm. If the population mean is known to be 18.5 cm, determine the population standard deviation. Assume that the radius values are normally distributed. Round your answer to two (2) decimal places. Do not include units.

Respuesta :

The population standard deviation for the watermelons will be 3.02

What is standard deviation?

The standard deviation is a statistic that measures the dispersion of a dataset relative to its mean and is calculated as the square root of the variance.

Now it is given that

[tex]p(15 < x < 22)=0.754[/tex]

[tex]r=18.5\\\\\\p(15 < x < 22)=0.754\\\\\\Z=\pm1.16\\\\\\Z=\dfrac{x-\mu}{\sigma}\\\\\\-1.16=\dfrac{15-18.5}{\sigma}\\\\\\\sigma=\dfrac{-3.5}{-1.16}\\\\\\\sigma=3.01\\\\\\Z=\dfrac{x-\mu}{\sigma}\\\\\\1.16=\dfrac{22-18.5}{\sigma}\\\\\\\sigma=3.01[/tex]

So the population standard deviation for the watermelons will be 3.02

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