[tex]\qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &18000\\ r=rate\to 14.3\%\to \frac{14.3}{100}\dotfill &0.143\\ t=years \end{cases} \\\\\\ A=18000(1 - 0.143)^{t}\implies A=18000(0.857)^t \\\\\\ \textit{3 years later, t = 3}\qquad A=18000(0.857)^3\implies A\approx 11329.61[/tex]
