Using it's concept, it is found that the probabilities of each outcome are given by:
a) 0.01 = 1%.
b) 0.0111 = 1.11%.
A probability is given by the number of desired outcomes divided by the number of total outcomes.
Item a:
The number is replaced, hence for each trial there are 10 outcomes, and the probability of each is of 1/10, hence:
[tex]p = \frac{1}{10} \times \frac{1}{10} = \frac{1}{100} = 0.01[/tex]
Item b:
Not replaced, hence for the second trial the probability is of 1/9, hence:
[tex]p = \frac{1}{10} \times \frac{1}{9} = \frac{1}{9} = 0.0111[/tex]
More can be learned about probabilities at https://brainly.com/question/14398287
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