The distance between the similar charges is 0.753 m. The electric force is the inverse of the square of the distance.
Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.
The given data in the problem is;
q₁,q₂ are the charges = 1.6 ×10⁻¹⁹ C
R is the distance
F is the electric force=2.0×10²⁴ N
The electric force is found as;
[tex]\rm F = \frac{Kq_1q_2}{R^2} \\\\ \rm 2.0 \times 10^{28}= \frac{9\times 10^9 \times 1.6 \times 10^{-19}1.6\times 10^{-19} }{R^2} \\\\ R =0.753 \ m[/tex]
Hence, the distance between the similar charges is 0.753 m.
To learn more about the electric force, refer to the link;
https://brainly.com/question/1076352
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