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find the area of this triangle, round to the nearest tenth, I will give brainliest

12in 28.8in 18in
147degrees

find the area of this triangle round to the nearest tenth I will give brainliest 12in 288in 18in 147degrees class=

Respuesta :

Answer:

59.15 in^2

Step-by-step explanation:

Using Heron's formula

semiperimeter , s = 1/2 ( 28.8+18+12) = 29.4

Area = sqrt ( 29.4(29.4-28.8)(29.4-18)(29.4-12) ) = 59.15 in^2

mathstudent55

Answer:

area = 58.8 in.²

Step-by-step explanation:

This is the area of a trianlge when 2 sides and the included angle are known.

Known sides: 12 in., 18 in.

Included angle: 147°

area = (1/2)ab sin C

area = (0.5)(12 in.)(18 in.)(sin 147°)

area = 58.8 in.²

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