Answer:
hope it's help u
Step-by-step explanation:
[tex] the \: lcm \: of \: 2 \: and \: 9 \: is \: 18.so \: the \: lcd \: is \: 18 \\ \frac{11}{2} = \frac{11 \times 9}{2 \times 9} = \frac{99}{18 } \\ \frac{1}{9} = \frac{ 1\times 2 }{9 \times 2} = \frac{2}{18} \\ \frac{99}{18} > \frac{2}{18} [/tex]
