Respuesta :
The dimensions of the painting are 22 in and 12 in if the rectangular painting has a length that is ten inches more than the width.
What is the area of the rectangle?
It is defined as the space occupied by the rectangle which is planner 2-dimensional geometry.
The formula for finding the area of a rectangle is given by:
Area of rectangle = length × width
Let's suppose the dimensions of the painting are x and y
x is the length and y is the width of the painting.
x = y+10 ..(1)
(x+2)(y+2) = 336 ...(2)
Put x = y + 10 in the second equation, we get:
(y+10+2)(y+2) = 336
(y+12)(y+2) = 336
[tex]\rm y^2+2y+12y+24 = 336\\\\\rm y^2+14y-312=0[/tex]
After solving the above quadratic equation, we get:
y = 12 or y = -26
The width cannot be negative.
So y = 12 in
and x = y+10 = 12+10 = 22 in
Thus, the dimensions of the painting are 22 in and 12 in if the rectangular painting has a length that is ten inches more than the width.
Learn more about the rectangle here:
https://brainly.com/question/15019502
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