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Permethrin was widely used to control lice and other insects, but has been banned by the EPA recently due to its carcinogenic properties. A company suspected of producing it was investigated. A 12.95 gram suspected sample was taken from the company and analyzed using combustion analysis. 32.065 grams of CO2 and 11.485 g of H2O were produced. What is the empirical formula for the unknown chemical found at the company? If the molecular mass of permethrin is 213.29 amu, what is the molecular formula? Is the sample found at the company permethrin? How do you know? Assume it contains only C, H, and O.

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The empirical formula of the compound is C4H7O while the molecular formula is C12H21O3.

What is empirical formula?

The empirical formula is the simplest formula of the compound. From the data provided;

Mass of moles of Carbon= 32.065 g/44g/mol * 12/1 = 8.75 g

Number of moles of carbon =  8.75 g/12 g/mol = 0.73 moles

Mass of hydrogen = 11.485 g/18 g/mol * 2 = 1.32 g

Number of moles of hydrogen = 1.32 g/1 g/mol = 1.32 moles

Mass of oxygen =  12.95 g - [8.75 g + 1.32 g] = 2.88 g

Numer of moles of oxygen = 2.88 g/16 g/mol = 0.18 moles

Divide through by the lowest ratio;

C -  0.73 /0.18       H -  1.32 /0.18       O -   0.18 /0.18

C- 4          H - 7      O -1

The empirical formula is C4H7O

The molecular formula is obtained from;

[4(12) + 7(1) + 16]n = 213.29

n = 213.29/71

n =3

C12H21O3

Learn more about molecular formula:https://brainly.com/question/14425592

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