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Please please help. No fake answers
A company sells several sizes of the same design of trash cans. The trash cans consist of a
cylinder and a hemisphere. The smallest size trash can has the dimensions shown. Use 3.14
for n and round your answers to the nearest tenth.
6 in.
12 in.
What is the volume of the hemisphere?
V1 =
in3
What is the volume of the cylinder?
V2 =
in3
What is the total volume of the trash can to the nearest tenth of a cubic inch?
V₂ + V2=
in3

Please please help No fake answers A company sells several sizes of the same design of trash cans The trash cans consist of a cylinder and a hemisphere The smal class=

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The volume of the hemisphere is 56.25 in³, the volume of the cylinder is 339.12 in³, the total volume is 395.74 in³.

How to find the volumes?

We know that for a hemisphere of radius R, the volume is:

[tex]V = (2/3)*pi*R^3[/tex]

In this case, the radius of the hemisphere is 3 inches (half of the diameter) then we have:

[tex]V = (2/3)*3.14*(3in)^3 = 56.52 in^3[/tex]

For a cylinder of radius R and height H the volume is:

[tex]V = pi*R^2*H[/tex]

Here we have:

R = 3in

H = 12in

So the volume is:

[tex]V = 3.14*(3in)^2*12in = 339.12 in^3[/tex]

the sum of the volumes is:

[tex]T_v = 56.62in^3 + 339.12in^3 = 395.74 in^3[/tex]

If you want to learn more about volumes:

https://brainly.com/question/1972490

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