If 28.0 grams of a gas occupies 22.4 liters at STP, the gas could be carbon monoxide, CO
We understood from the ideal gas equation that 1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP)
To determine the identity of the gas, we shall determine the mass of 1 mole of each gas. This can be obtained as
For C₂H₂
1 mole of C₂H₂ = (12×2) + (2×1) = 26 g
For C₂H₆
1 mole of C₂H₆ = (12×2) + (6×1) = 30 g
For CO₂
1 mole of CO₂ = 12 + (16×2) = 44 g
For CO
I mole of CO = 12 + 16 = 28 g
From the above illustrations, we can see that 1 mole of CO is equivalent to 28 g.
Thus, the correct answer to the question is CO
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