Manu enjoys throwing spaghetti on his days off. He stands in his backyard every Saturday afternoon. His throwing arm is quite good; his record spaghetti toss was 12 feet in the air, after 4 seconds. At 2 seconds, the spaghetti is 8 feet high. At 5 seconds, it is at 4 feet. (i) Find the equation of his throw. (ii) How high is the spaghetti when he throws it?

Respuesta :

Manu enjoys throwing spaghetti on his days off. He stands in his backyard every Saturday afternoon, the equation of his throw and How high is the spaghetti  went  is mathematically given as

y=-10/3x^2+22x-68/3

x=0

What is the equation of his throw and how high is the spaghetti went?

Generally, the equation for the three sceneario equations are is mathematically given as

16a+4b+c=12(4,12)

4a+2b+c=8(2,8)

25a+5b+c4(5,4)

Now solving the matrix we have

a=-10/3

b=22

c=-68/3

Therefore, the equation is

y=ax^2+bx+c

y=-10/3x^2+22x-68/3

In conclusion, considering his throws starting point

s=-68/3, -ve show below the surface and with time as zero

x=0

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