Question 3:
- [tex]f(x)=(\frac{2}{3})x^2+3x-2\\[/tex]⇒standard form
- [tex]f(x)=3x^2-8x+5(3x-8)[/tex]⇒intercept form
- [tex]f(x)=4(x-5)^2+20[/tex]⇒ vertex form
- [tex]f(x)=-(3x-8)(3x+5)[/tex]⇒none of the above
Question 4:Explain in detail how to solve the following function by completing the square:
[tex]x^2+8x-9=0[/tex]
1. move the term to left side (done)
[tex]x^2+8x-9=0[/tex]
2. use the quadratic formula
[tex]x=\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]
A=1
B=8
C=-9
[tex]x=\frac{-(8)+\sqrt{(8)^2-4(1)(-9)} }{2(1)}[/tex]
x=1
now check your answer.
1^2+8(1)-9=0
