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A water cup in the shape of a cone has a height of 4 inches and a maximum diameter of 3 inches. What is the volume of the water in the cup, to the nearest tenth of a cubic inch, when the cup is filled to half its height?

Respuesta :

rinads

The diameter of half the cone is equal to half of the given diameter and its height is also half the given height.                          
        V = 1/3(πr²)(h)d = 1.5 inches, r = 0.75 inchesh = 2 inchesSubstituting,                                   V = 1/3(π)(0.75 in)²(2 in)                                   


      V = 1.178 in³

GeorgePP

Answer:

4.7in^3

Step-by-step explanation:

The volume of a cone is given by the formula:

[tex]V=\frac{\pi r^2h}{3}[/tex]

The given information is:

[tex]h=4in[/tex]

[tex]d=3in[/tex]

[tex]r=1.5in[/tex]

The cone is filled up to half, therefore the height at which the water peaks is 1/2 of 4 inches, which is 2in. Plug this information into the volume formula to get:

[tex]V=\frac{2\pi (1.5^)^2}{3}=4.7in^3[/tex]

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