Answer:
[tex]2x - 2y = 24 \\ 2(x - y) = 24 \\ x = 12 + y......eq(1) \\ 4x + 7y = - 40......eq(2) \\ substituting \: the \: value \: of \: x \: in \: eq(2) \\ 4(12 + y) + 7y = - 40 \\ 48 + 4y + 7y = - 40 \\ 11y = - 40 - 48 \\ y = \frac{ - 88}{11} \\ y = - 8 \\ putting \: the \: value \: of \: y \: im \: eq(1) \\ x = 12 - 8 \\ = 4[/tex]
Step-by-step explanation:
3x-2y=24......eqi
x+2y=48........eqii
now solving eq i&ii
4x=72
x=72/4
x=18
now putting the value of x in eqii
18+2y=48
2y=48-18
y=30/2
y=15
