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fieryanswererft

Tyler concludes that 5x² will always have a larger output for the same value of x.

Look at the graph below and the table given

Take a random value: x = 0

  • When 5x², y = 0
  • When 2^x, y = 1

Here, 1 > 0, making 2^x > 5x²

Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.

Disagree with Tyler's point.

Ver imagen fieryanswererft

No it won't be

Take x =9

  • 2^x=2^9=512

But

  • 5(9)²=5(81)=405

Clearly 2^x surpasses 5x²

So Tyler is wrong

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