Respuesta :

The mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.

What is Kinetic Energy?

Kinetic energy is simply a form of energy that a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given the data in the question;

  • Velocity of the bullet v = 970m/s
  • Kinetic energy of the bullet K = 3.0 × 10³J = 3000kgm²/s²
  • Mass of the bullet m = ?

We substitute our given values into the expression above.

K = (1/2)mv²

3000kgm²/s² = 0.5 × m × (970m/s)²

3000kgm²/s² = 0.5 × m × 940900m²/s²

3000kgm²/s² = m × 470450m²/s²

m = 3000kgm²/s² ÷ 470450m²/s²

m = 0.00064kg

m = 6.4 × 10⁻⁴kg

Therefore, the mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.

Learn more about kinetic energy here: brainly.com/question/12669551

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