You have a standard deck of 52 cards. Find the probability of drawing one card, then drawing another without replacement.
A) You draw an even-numbered card and then a face card.
B) Both cards you drew are "4" or higher (if aces are considered low cards and face cards are nonnumerical)
C) You drew a black face card and then a black "5".

A) The probability of drawing an even-numbered card is given by the quotient between the number of even-numbered cards and the total number of cards.

On the 52 card deck, there are 16 even cards (2, 4, 6, 8 for each type), so the probability is:

p = 16/52

Then the probability of drawing a face card is given in the same way, notice that now there are 51 cards in the deck and 12 face cards, so we get:

q = 12/51

The joint probability is the product of these two:

P = (16/52)*(12/51) = 0.07

b) Both cards are 4 or larger.

There are 6 cards equal or larger than 4 for each type, so the probability for the first card is:

p = 24/52

For the second card, there is one card less in the deck (and one card less that is equal or larger than 4) so the probability is:

q = 23/51

The joint probability is:

P = (24/52)*(23/51) = 0.21

C) There are 6 black face cards, so the probability first is:

p = 6/52

Then there are 2 black cards with the number 5, so the probability is:

q = 2/51

The joint probability is:

P = (6/52)*(2/51) = 0.001

If you want to learn more about probabilities:

https://brainly.com/question/25870256

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