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The distribution of the number of words in text messages between employees at a large company is skewed right
with a mean of 8.6 words and a standard deviation of 4.3 words. If a random sample of 39 messages is selected,
what is the probability the sample mean is more than 10 words?
0.0210
0.2454
0.3724
0.9790

Respuesta :

raphealnwobi

The probability the sample mean is more than 10 words for a random sample of 39 messages is 2.12%

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The z score is given by:

z = (raw score - mean) / (standard deviation / √sample size)

Given mean of 8.6 words and a standard deviation of 4.3 words. If a random sample of 39 messages, hence, for x > 10:

z = (10 - 8.6) / (4.3 / √39) = 2.03

P(x > 10) = P(z > 2.03) = 1 - P(z < 2.03) = 1 - 0.9788 = 0.0212

The probability the sample mean is more than 10 words for a random sample of 39 messages is 2.12%

Find out more on equation at: https://brainly.com/question/2972832

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Answer:

A. .0210

Step-by-step explanation:

I'm taking the test... could be wrong though...