Respuesta :
AREA
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[tex] \large \sf \underline{Question:}[/tex]
- The area of a rectangle is 48 cm². If its wdth is 6 cm, what is its length
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[tex] \large \sf \underline{Answer:}[/tex]
[tex] \qquad \qquad \qquad \huge \bold{8cm}[/tex]
To solve for the area of rectangle, you use this formula A = length × width. But we're doing it reversal, we will divide the width to the area
- [tex]\large\tt{A \: = \: l \: \times \: w}[/tex]
- [tex]\large\tt{48cm^{2} \: = \: l \: \times \: 6cm}[/tex]
- [tex]\large\tt{48cm^{2} \: \div \: 6cm \: = \: l}[/tex]
- [tex]\large\tt{48cm^{2} \: \div \: 6cm \: = \: \pmb{8cm}}[/tex]
Therefore, The length is 8cm.
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Hey ! there
Answer:
- Length of rectangle is 8 cm .
Step-by-step explanation:
In this question we are provided with a rectangle having area 48 cm² and width 6 cm . We are asked to find the length of rectangle .
We know that ,
[tex] \qquad \qquad\underline{\boxed{\frak{Area_{(Rectangle)} = l \times w}}}[/tex]
Where ,
- l refers to Length
- w refers to Width
SOLUTION : -
We are finding value of length by substituting value of width as 6 cm and area as 48 cm² in the formula . So ,
[tex] \quad\longmapsto \qquad \:48 = 6 \times l[/tex]
or ,
[tex] \quad\longmapsto \qquad \:48 = 6l[/tex]
Dividing with 6 on both sides :
[tex] \quad\longmapsto \qquad \: \cancel{\dfrac{48}{6}} = \dfrac{ \cancel{6}l}{ \cancel{6}} [/tex]
We get ,
[tex] \quad\longmapsto \qquad \: \orange{\underline{\boxed{ \frak{l = 8 \: cm}}}} \quad \bigstar[/tex]
- Henceforth , Length of rectangle having area 48 cm² and width 6 cm is ❝ 8 cm ❞
Verifying : -
We are verifying our answer by substituting value of length and width in formula and equating it with given area . So ,
- [tex] 8 \times 6 = 48[/tex]
- [tex]48 = 48[/tex]
- [tex] \rm{L.H.S = R.H.S}[/tex]
- [tex] \rm{Hence , \: Verified .}[/tex]
Therefore , our answer is correct .
