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[tex]\diamond\large\blue\textsf{\textbf{\underline{Given question:-}}}[/tex]
What is the S.I. form of the equation that passes through (-6,3) and is parallel to y=2x-3?
[tex]\diamond\large\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}[/tex]
Parallel lines have the same slope.
[tex]\bigstar[/tex] The line y=2x-3 has a slope of 2, therefore, the line parallel to it has a slope of 2.
Now let's write the equation of the new line in point-slope form:-
[tex]\sf{y-y_1=m(x-x_1)}[/tex]
Replace y1 with -3, m with 2, and then write -6 in lieu of x1:-
[tex]\sf{y-(-3)=2(x-(-6)}[/tex]
On simplification,
[tex]\sf{y+3=2(x+6)}[/tex]
On further simplification,
[tex]\sf{y=2x+12-3}[/tex]
Which results in:-
[tex]\sf{y=2x-9}[/tex]
▲ our slope-intercept equation
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