If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm,
the new volume to the correct number of significant digits is:
O 3 ml
O 12mL
O 24 ml
O 13 ml
O none of these choices

Now, In the question, the number of moles remains the same as the gas is the same. so n is constant so we can compare n before and after a temperature change.

[tex]\frac{P1V1}{RT1}[/tex] = [tex]\frac{P2V2}{RT2}[/tex]

where P1= 1 atm, P2 = 10 atm, V1= 20 mL, T1= 10°C and T2= 100°C

We don't have to worry about the standard units as they are present equally on both the sides and get cut, same goes for R( gas constant)

So putting values, we get

[tex]\frac{1*20}{R*10} = \frac{10*V2}{R*100}[/tex]

Cutting, R on both sides and moving contents to the right so that only V2 is left on the left.

[tex]\frac{1*20*100}{10*10} = V2[/tex]

∴ V2 = [tex]\frac{2000}{100}[/tex]

∴ V2 = 20mL

If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm, the new volume to the correct number of significant digits is: O 3 ml O 12mL O 24 ml O 13 ml O none of these choices

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If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm,
the new volume to the correct number of significant digits is:
O 3 ml
O 12mL
O 24 ml
O 13 ml
O none of these choices