- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
[tex]\diamond\large\textsf{\textbf{\underline{Given question:-}}}[/tex]
Solve the following equation for b.
13b=6b+14
[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}[/tex]
❖ First of all, we need to make sure that all the variables are on one side (the left-hand side, LHS) and numbers are on the right-hand side, RHS.
Here we have variables on the right-hand side, so we can move that term to the left-hand side, making sure to use the opposite operation:-
13b=6b+14 Subtract 6b on both sides, which results in:-
7b=14 Divide by 7 on both sides, which results in:-
b=2 We've found the value of b. Now, we need to check our solution by replacing b with the value of b, 2, and seeing whether or not we end up with a true statement:-
13(2)=6(2)+14 Multiply.
26=12+14 Now add.
26=26 Since the left-hand side does equal the right-hand side, we conclude that our solution, b=2, is correct.
Good luck with your studies.
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
