Given the function g(x) = x2 + 10x + 20, determine the average rate of change of
the function over the interval -9 < x < 0.

Respuesta :

A function assigns the values. The average rate of change for the given function g(x) is 1.

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

The average rate of change of a function is given by the formula,

Average rate of change, = [f(b)-f(a)]/(b-a), [a,b]

Where a is the lower limit and b is the upper limit.

Given the upper limit for the function is 0, therefore, the value of a is 0, similarly, the value of b is -9. Thus,

a = 0

g(a) = 0²+10(0)+20 = 20

b = -9

g(b) = (-9)²+10(-9)+20 = 11

The average rate of change for the function g(x), can be written as,

[tex]\text{Average rate of change}= \dfrac{g(-9)-g(0)}{-9-0}=\dfrac{11-20}{-9} = 1[/tex]

Hence, the average rate of change for the given function g(x) is 1.

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