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[tex]\diamond\large\blue\textsf{\textbf{\underline{Given question:-}}}[/tex]
What is the equation of the line that passes through (-3, 6) and has a slope of -2?
[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}\diamond[/tex]
First, we need to write the equation of the line in point-slope form:-
[tex]\sf{y-y_1=m(x-x_1)}[/tex]
Replace y1 with 6, m with -2, and x1 with -3:-
[tex]\sf{y-6=-2(x-(-3)}[/tex]
On simplification,
[tex]\sf{y-6=-2(x+3)}[/tex]
On further simplification,
[tex]\sf{y-6=-2x-6}[/tex]
Add 6 on both sides:-
[tex]\it{y=-2x}[/tex]
Good luck with your studies.
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